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Date: Fri, 7 Nov 2008 14:43:15 -0600
From: Peter Groves <pdgroves at gmail.com>
To: "Angela Zhu" <angela22.zhu at gmail.com>
Subject: Re: [Lablgtk] How to get mouse position continuously without events
Message-Id: <20081107144315.6462ea61.pdgroves at gmail.com>
In-Reply-To: <f82e818a0811070956l2fdc6e45u74dde431f90d30c9 at mail.gmail.com>
References: <f82e818a0811070956l2fdc6e45u74dde431f90d30c9 at mail.gmail.com>
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Cc: lablgtk at yquem.inria.fr

The Widget class has a method called "pointer" that gives the location
of the mouse pointer. Here is the doc from the gtk core library:

http://library.gnome.org/devel/gtk/2.14/GtkWidget.html#gtk-widget-get-pointer

I have not tried to use it using lablgtk, however, so I can't tell you
much about how to use it.

-Peter

On Fri, 7 Nov 2008 11:56:34 -0600
"Angela Zhu" <angela22.zhu@gmail.com> wrote:

> Hi,
> I am writing a simulation program, where basically, the program has a
> number of
> time steps. At each time step, it tries to get the current position of
> mouse,
> do some computation, and update a gui with the result computed.
> 
> What I need is a function that can get the current position of mouse
> without any
> events. I know, for example, the following code will work.
> But is there a way to avoid events, but just get the mouse position?
> 
> Thanks a lot in advance!
> 
> 
> method handle_event = function
> 
>     | info (* : GdkEvent.Motion.t *) ->
> 
>     let new_x = (GdkEvent.Motion.x info) -. 350.
> 
>         and new_y = (GdkEvent.Motion.y info) -. 350.
> 
> in
> 
>   print_string "\nfollow mouse\n"; flush stdout;
> 
>   inputs.(0)#move_to new_x new_y;
> 
>   false
> 
>     | _ ->  false
> 
> 
>       ignore (canvas#event#connect#motion_notify
> 
> ~callback:(self#handle_event));
> 
> 
> 
> -- 
> Regards,
> Angela Zhu
> ------------------------------------------
> Dept. of CS, Rice University
> http://www.cs.rice.edu/~yz2/
> ------------------------------------------
> 

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